Base | Representation |
---|---|
bin | 1100100000010000100… |
… | …0000100110010010011 |
3 | 202112111000012021021120 |
4 | 3020010020010302103 |
5 | 12004421300343134 |
6 | 242404050253323 |
7 | 21343244251035 |
oct | 3100410046223 |
9 | 675430167246 |
10 | 214817590419 |
11 | 83115a251a3 |
12 | 35771b87243 |
13 | 1734612c663 |
14 | a57bdc1c55 |
15 | 58c4256649 |
hex | 3204204c93 |
214817590419 has 4 divisors (see below), whose sum is σ = 286423453896. Its totient is φ = 143211726944.
The previous prime is 214817590417. The next prime is 214817590511. The reversal of 214817590419 is 914095718412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 214817590419 - 21 = 214817590417 is a prime.
It is a super-2 number, since 2×2148175904192 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (214817590417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35802931734 + ... + 35802931739.
It is an arithmetic number, because the mean of its divisors is an integer number (71605863474).
Almost surely, 2214817590419 is an apocalyptic number.
214817590419 is a deficient number, since it is larger than the sum of its proper divisors (71605863477).
214817590419 is an equidigital number, since it uses as much as digits as its factorization.
214817590419 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71605863476.
The product of its (nonzero) digits is 725760, while the sum is 51.
The spelling of 214817590419 in words is "two hundred fourteen billion, eight hundred seventeen million, five hundred ninety thousand, four hundred nineteen".
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