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2148996998411 = 9912168513621
BaseRepresentation
bin11111010001011010001…
…100111110010100001011
321121102221021222121022122
4133101122030332110023
5240202121212422121
64323122515441455
7311155102044314
oct37213214762413
97542837877278
102148996998411
11759425865aaa
122a85a68b628b
1312785a095363
1476024d5160b
153ad789d65ab
hex1f45a33e50b

2148996998411 has 4 divisors (see below), whose sum is σ = 2151165513024. Its totient is φ = 2146828483800.

The previous prime is 2148996998399. The next prime is 2148996998441. The reversal of 2148996998411 is 1148996998412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2148996998411 - 234 = 2131817129227 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2148996998441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1084255820 + ... + 1084257801.

It is an arithmetic number, because the mean of its divisors is an integer number (537791378256).

Almost surely, 22148996998411 is an apocalyptic number.

2148996998411 is a deficient number, since it is larger than the sum of its proper divisors (2168514613).

2148996998411 is an equidigital number, since it uses as much as digits as its factorization.

2148996998411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2168514612.

The product of its digits is 80621568, while the sum is 71.

Subtracting from 2148996998411 its reverse (1148996998412), we obtain a palindrome (999999999999).

The spelling of 2148996998411 in words is "two trillion, one hundred forty-eight billion, nine hundred ninety-six million, nine hundred ninety-eight thousand, four hundred eleven".

Divisors: 1 991 2168513621 2148996998411