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2151315135323 = 10212172106619
BaseRepresentation
bin11111010011100100010…
…111111101101101011011
321121122220211222011100022
4133103210113331231123
5240221343133312243
64324144525301055
7311266410635054
oct37234427755533
97548824864308
102151315135323
1175a405344632
122a8b3310478b
13127b3941a8c3
14761a4b8172b
153ae6228bb68
hex1f4e45fdb5b

2151315135323 has 4 divisors (see below), whose sum is σ = 2151318263160. Its totient is φ = 2151312007488.

The previous prime is 2151315135317. The next prime is 2151315135367. The reversal of 2151315135323 is 3235315131512.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2151315135323 - 210 = 2151315134299 is a prime.

It is a super-4 number, since 4×21513151353234 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2151315131323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32093 + ... + 2074526.

It is an arithmetic number, because the mean of its divisors is an integer number (537829565790).

Almost surely, 22151315135323 is an apocalyptic number.

2151315135323 is a deficient number, since it is larger than the sum of its proper divisors (3127837).

2151315135323 is a wasteful number, since it uses less digits than its factorization.

2151315135323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3127836.

The product of its digits is 40500, while the sum is 35.

The spelling of 2151315135323 in words is "two trillion, one hundred fifty-one billion, three hundred fifteen million, one hundred thirty-five thousand, three hundred twenty-three".

Divisors: 1 1021217 2106619 2151315135323