Base | Representation |
---|---|
bin | 110000111010100111001100… |
… | …001010100010010100010011 |
3 | 1001012201121120022000220002020 |
4 | 300322213030022202110103 |
5 | 211144224004301002121 |
6 | 2041315114204422523 |
7 | 63212631055451232 |
oct | 6072471412422423 |
9 | 1035647508026066 |
10 | 215134042203411 |
11 | 62603920322231 |
12 | 20166503547a43 |
13 | 930708c960306 |
14 | 3b1a786782b19 |
15 | 19d11e43771c6 |
hex | c3a9cc2a2513 |
215134042203411 has 4 divisors (see below), whose sum is σ = 286845389604552. Its totient is φ = 143422694802272.
The previous prime is 215134042203317. The next prime is 215134042203499. The reversal of 215134042203411 is 114302240431512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 215134042203411 - 211 = 215134042201363 is a prime.
It is a super-2 number, since 2×2151340422034112 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (215134042243411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35855673700566 + ... + 35855673700571.
It is an arithmetic number, because the mean of its divisors is an integer number (71711347401138).
Almost surely, 2215134042203411 is an apocalyptic number.
215134042203411 is a deficient number, since it is larger than the sum of its proper divisors (71711347401141).
215134042203411 is an equidigital number, since it uses as much as digits as its factorization.
215134042203411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71711347401140.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 215134042203411 its reverse (114302240431512), we get a palindrome (329436282634923).
The spelling of 215134042203411 in words is "two hundred fifteen trillion, one hundred thirty-four billion, forty-two million, two hundred three thousand, four hundred eleven".
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