2151403613841 has 4 divisors (see below), whose sum is σ = 2868538151792. Its totient is φ = 1434269075892.

The previous prime is 2151403613839. The next prime is 2151403613867. The reversal of 2151403613841 is 1483163041512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2151403613841 - 2¹ = 2151403613839 is a prime.

It is a super-2 number, since 2×2151403613841² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2151403613841.

It is not an unprimeable number, because it can be changed into a prime (2151403613341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358567268971 + ... + 358567268976.

It is an arithmetic number, because the mean of its divisors is an integer number (717134537948).

Almost surely, 2^{2151403613841} is an apocalyptic number.

It is an amenable number.

2151403613841 is a deficient number, since it is larger than the sum of its proper divisors (717134537951).

2151403613841 is an equidigital number, since it uses as much as digits as its factorization.

2151403613841 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 717134537950.

The product of its (nonzero) digits is 69120, while the sum is 39.

The spelling of 2151403613841 in words is "two trillion, one hundred fifty-one billion, four hundred three million, six hundred thirteen thousand, eight hundred forty-one".