Base | Representation |
---|---|
bin | 11111010100100000010… |
… | …101110110011100011011 |
3 | 21121202111222002021011020 |
4 | 133110200111312130123 |
5 | 240230423212323420 |
6 | 4324432425133523 |
7 | 311333345314533 |
oct | 37244025663433 |
9 | 7552458067136 |
10 | 2152321214235 |
11 | 75a88123a605 |
12 | 2a917402a2a3 |
13 | 127c699a597a |
14 | 7625c6324c3 |
15 | 3aec076e340 |
hex | 1f52057671b |
2152321214235 has 8 divisors (see below), whose sum is σ = 3443713942800. Its totient is φ = 1147904647584.
The previous prime is 2152321214213. The next prime is 2152321214237. The reversal of 2152321214235 is 5324121232512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2152321214235 - 213 = 2152321206043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2152321214196 and 2152321214205.
It is not an unprimeable number, because it can be changed into a prime (2152321214237) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71744040460 + ... + 71744040489.
It is an arithmetic number, because the mean of its divisors is an integer number (430464242850).
Almost surely, 22152321214235 is an apocalyptic number.
2152321214235 is a deficient number, since it is larger than the sum of its proper divisors (1291392728565).
2152321214235 is a wasteful number, since it uses less digits than its factorization.
2152321214235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143488080957.
The product of its digits is 28800, while the sum is 33.
Adding to 2152321214235 its reverse (5324121232512), we get a palindrome (7476442446747).
The spelling of 2152321214235 in words is "two trillion, one hundred fifty-two billion, three hundred twenty-one million, two hundred fourteen thousand, two hundred thirty-five".
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