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2152541161 = 12716949143
BaseRepresentation
bin1000000001001101…
…0010101111101001
312120000101102100201
42000103102233221
513402022304121
6553332232201
7104225204131
oct20023225751
95500342321
102152541161
11a05065041
12500a6b661
13283c55ac4
14165c45ac1
15c8e94e91
hex804d2be9

2152541161 has 4 divisors (see below), whose sum is σ = 2169490432. Its totient is φ = 2135591892.

The previous prime is 2152541143. The next prime is 2152541177. The reversal of 2152541161 is 1611452512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2152541161 - 25 = 2152541129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2152541561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8474445 + ... + 8474698.

It is an arithmetic number, because the mean of its divisors is an integer number (542372608).

Almost surely, 22152541161 is an apocalyptic number.

It is an amenable number.

2152541161 is a deficient number, since it is larger than the sum of its proper divisors (16949271).

2152541161 is a wasteful number, since it uses less digits than its factorization.

2152541161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16949270.

The product of its digits is 2400, while the sum is 28.

The square root of 2152541161 is about 46395.4864291776. The cubic root of 2152541161 is about 1291.1711738307.

Adding to 2152541161 its reverse (1611452512), we get a palindrome (3763993673).

The spelling of 2152541161 in words is "two billion, one hundred fifty-two million, five hundred forty-one thousand, one hundred sixty-one".

Divisors: 1 127 16949143 2152541161