Base | Representation |
---|---|
bin | 11111010101010000001… |
… | …110010001010001100001 |
3 | 21121211120221200002210212 |
4 | 133111100032101101201 |
5 | 240234044340031340 |
6 | 4325044243103505 |
7 | 311362301364002 |
oct | 37252016212141 |
9 | 7554527602725 |
10 | 2153124533345 |
11 | 7601537380a5 |
12 | 2a9359071b95 |
13 | 12806724b516 |
14 | 762d71c31a9 |
15 | 3b01b04ea65 |
hex | 1f550391461 |
2153124533345 has 16 divisors (see below), whose sum is σ = 2597250776400. Its totient is φ = 1713499521024.
The previous prime is 2153124533303. The next prime is 2153124533347. The reversal of 2153124533345 is 5433354213512.
It can be written as a sum of positive squares in 8 ways, for example, as 41982370816 + 2111142162529 = 204896^2 + 1452977^2 .
It is a cyclic number.
It is not a de Polignac number, because 2153124533345 - 236 = 2084405056609 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2153124533347) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34725431 + ... + 34787379.
It is an arithmetic number, because the mean of its divisors is an integer number (162328173525).
Almost surely, 22153124533345 is an apocalyptic number.
It is an amenable number.
2153124533345 is a deficient number, since it is larger than the sum of its proper divisors (444126243055).
2153124533345 is a wasteful number, since it uses less digits than its factorization.
2153124533345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98164.
The product of its digits is 648000, while the sum is 41.
Adding to 2153124533345 its reverse (5433354213512), we get a palindrome (7586478746857).
The spelling of 2153124533345 in words is "two trillion, one hundred fifty-three billion, one hundred twenty-four million, five hundred thirty-three thousand, three hundred forty-five".
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