Base | Representation |
---|---|
bin | 11111010101100001010… |
… | …100011000111001011001 |
3 | 21121212022221100220102211 |
4 | 133111201110120321121 |
5 | 240240141301200410 |
6 | 4325132530355121 |
7 | 311402353315321 |
oct | 37254124307131 |
9 | 7555287326384 |
10 | 2153411350105 |
11 | 760290627844 |
12 | 2a941912baa1 |
13 | 1280b17b1892 |
14 | 76323324281 |
15 | 3b03630768a |
hex | 1f561518e59 |
2153411350105 has 4 divisors (see below), whose sum is σ = 2584093620132. Its totient is φ = 1722729080080.
The previous prime is 2153411350087. The next prime is 2153411350117. The reversal of 2153411350105 is 5010531143512.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1185102213376 + 968309136729 = 1088624^2 + 984027^2 .
It is not a de Polignac number, because 2153411350105 - 229 = 2152874479193 is a prime.
It is a super-2 number, since 2×21534113501052 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215341135006 + ... + 215341135015.
It is an arithmetic number, because the mean of its divisors is an integer number (646023405033).
Almost surely, 22153411350105 is an apocalyptic number.
It is an amenable number.
2153411350105 is a deficient number, since it is larger than the sum of its proper divisors (430682270027).
2153411350105 is an equidigital number, since it uses as much as digits as its factorization.
2153411350105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 430682270026.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 2153411350105 its reverse (5010531143512), we get a palindrome (7163942493617).
The spelling of 2153411350105 in words is "two trillion, one hundred fifty-three billion, four hundred eleven million, three hundred fifty thousand, one hundred five".
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