Base | Representation |
---|---|
bin | 1100100010001101110… |
… | …1100100110010001011 |
3 | 202120211122110002222001 |
4 | 3020203131210302023 |
5 | 12012010342221303 |
6 | 242532150411431 |
7 | 21362260006654 |
oct | 3104335446213 |
9 | 676748402861 |
10 | 215343320203 |
11 | 83365765820 |
12 | 3589a060b77 |
13 | 173cb022b7b |
14 | a5cbb5452b |
15 | 59054a331d |
hex | 3223764c8b |
215343320203 has 8 divisors (see below), whose sum is σ = 234969993216. Its totient is φ = 195724981800.
The previous prime is 215343320201. The next prime is 215343320207. The reversal of 215343320203 is 302023343512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 215343320203 - 21 = 215343320201 is a prime.
It is a super-2 number, since 2×2153433202032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (215343320201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2029563 + ... + 2133028.
It is an arithmetic number, because the mean of its divisors is an integer number (29371249152).
Almost surely, 2215343320203 is an apocalyptic number.
215343320203 is a deficient number, since it is larger than the sum of its proper divisors (19626673013).
215343320203 is a wasteful number, since it uses less digits than its factorization.
215343320203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4167305.
The product of its (nonzero) digits is 12960, while the sum is 28.
Adding to 215343320203 its reverse (302023343512), we get a palindrome (517366663715).
The spelling of 215343320203 in words is "two hundred fifteen billion, three hundred forty-three million, three hundred twenty thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.101 sec. • engine limits •