Base | Representation |
---|---|
bin | 11111010101101111100… |
… | …100000000001010001011 |
3 | 21121212221121001001010210 |
4 | 133111233210000022023 |
5 | 240241133440332412 |
6 | 4325212344412203 |
7 | 311411314465452 |
oct | 37255744001213 |
9 | 7555847031123 |
10 | 2153650324107 |
11 | 7603a350a517 |
12 | 2a9485177063 |
13 | 12811c163709 |
14 | 76346d6db99 |
15 | 3b04c2ae83c |
hex | 1f56f90028b |
2153650324107 has 4 divisors (see below), whose sum is σ = 2871533765480. Its totient is φ = 1435766882736.
The previous prime is 2153650324103. The next prime is 2153650324109. The reversal of 2153650324107 is 7014230563512.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2153650324107 - 22 = 2153650324103 is a prime.
It is a super-2 number, since 2×21536503241072 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2153650324103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358941720682 + ... + 358941720687.
It is an arithmetic number, because the mean of its divisors is an integer number (717883441370).
Almost surely, 22153650324107 is an apocalyptic number.
2153650324107 is a deficient number, since it is larger than the sum of its proper divisors (717883441373).
2153650324107 is an equidigital number, since it uses as much as digits as its factorization.
2153650324107 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 717883441372.
The product of its (nonzero) digits is 151200, while the sum is 39.
Adding to 2153650324107 its reverse (7014230563512), we get a palindrome (9167880887619).
The spelling of 2153650324107 in words is "two trillion, one hundred fifty-three billion, six hundred fifty million, three hundred twenty-four thousand, one hundred seven".
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