Base | Representation |
---|---|
bin | 1100100010011011011… |
… | …1100001101111011011 |
3 | 202120222121221212100111 |
4 | 3020212313201233123 |
5 | 12012120004031011 |
6 | 242541551145151 |
7 | 21363552442051 |
oct | 3104667415733 |
9 | 676877855314 |
10 | 215400455131 |
11 | 83394a3a074 |
12 | 358b52151b7 |
13 | 17409b08a14 |
14 | a5d55881d1 |
15 | 590a4dc121 |
hex | 3226de1bdb |
215400455131 has 4 divisors (see below), whose sum is σ = 215891117200. Its totient is φ = 214909793064.
The previous prime is 215400455099. The next prime is 215400455147. The reversal of 215400455131 is 131554004512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 215400455131 - 25 = 215400455099 is a prime.
It is a super-2 number, since 2×2154004551312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 215400455093 and 215400455102.
It is not an unprimeable number, because it can be changed into a prime (215400450131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245330376 + ... + 245331253.
It is an arithmetic number, because the mean of its divisors is an integer number (53972779300).
Almost surely, 2215400455131 is an apocalyptic number.
215400455131 is a deficient number, since it is larger than the sum of its proper divisors (490662069).
215400455131 is an equidigital number, since it uses as much as digits as its factorization.
215400455131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 490662068.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 215400455131 its reverse (131554004512), we get a palindrome (346954459643).
The spelling of 215400455131 in words is "two hundred fifteen billion, four hundred million, four hundred fifty-five thousand, one hundred thirty-one".
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