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2154763489145 = 51812123781949
BaseRepresentation
bin11111010110110001111…
…010011000111101111001
321121222211011122200111112
4133112301322120331321
5240300423423123040
64325515031410105
7311451022312541
oct37266172307571
97558734580445
102154763489145
117609148a6923
122a9735b23935
13128268973757
1476410b38321
153b0b4d96365
hex1f5b1e98f79

2154763489145 has 8 divisors (see below), whose sum is σ = 2585858987400. Its totient is φ = 1723715591040.

The previous prime is 2154763489141. The next prime is 2154763489199. The reversal of 2154763489145 is 5419843674512.

It can be written as a sum of positive squares in 4 ways, for example, as 29897522281 + 2124865966864 = 172909^2 + 1457692^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2154763489145 - 22 = 2154763489141 is a prime.

It is a super-3 number, since 3×21547634891453 (a number of 38 digits) contains 333 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (2154763489141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11800370 + ... + 11981579.

It is an arithmetic number, because the mean of its divisors is an integer number (323232373425).

Almost surely, 22154763489145 is an apocalyptic number.

It is an amenable number.

2154763489145 is a deficient number, since it is larger than the sum of its proper divisors (431095498255).

2154763489145 is a wasteful number, since it uses less digits than its factorization.

2154763489145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23800075.

The product of its digits is 29030400, while the sum is 59.

The spelling of 2154763489145 in words is "two trillion, one hundred fifty-four billion, seven hundred sixty-three million, four hundred eighty-nine thousand, one hundred forty-five".

Divisors: 1 5 18121 90605 23781949 118909745 430952697829 2154763489145