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215503430147 = 375824417031
BaseRepresentation
bin1100100010110100000…
…0010110001000000011
3202121020210201112111222
43020231000112020003
512012322334231042
6243000110225255
721366242634545
oct3105500261003
9677223645458
10215503430147
1183438082795
12359237b522b
1317425251695
14a605111695
15591457d2d2
hex322d016203

215503430147 has 4 divisors (see below), whose sum is σ = 221327847216. Its totient is φ = 209679013080.

The previous prime is 215503430123. The next prime is 215503430167. The reversal of 215503430147 is 741034305512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 215503430147 - 28 = 215503429891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (215503430167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2912208479 + ... + 2912208552.

It is an arithmetic number, because the mean of its divisors is an integer number (55331961804).

Almost surely, 2215503430147 is an apocalyptic number.

215503430147 is a deficient number, since it is larger than the sum of its proper divisors (5824417069).

215503430147 is an equidigital number, since it uses as much as digits as its factorization.

215503430147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5824417068.

The product of its (nonzero) digits is 50400, while the sum is 35.

Adding to 215503430147 its reverse (741034305512), we get a palindrome (956537735659).

The spelling of 215503430147 in words is "two hundred fifteen billion, five hundred three million, four hundred thirty thousand, one hundred forty-seven".

Divisors: 1 37 5824417031 215503430147