Base | Representation |
---|---|
bin | 11111010111000110001… |
… | …011001101111011111011 |
3 | 21122000200212100012220011 |
4 | 133113012023031323323 |
5 | 240302122440212411 |
6 | 4330012454042351 |
7 | 311462321013646 |
oct | 37270613157373 |
9 | 7560625305804 |
10 | 2155103444731 |
11 | 760a79790556 |
12 | 2a980b9493b7 |
13 | 1282c1220ac3 |
14 | 76443d4ca5d |
15 | 3b0d4b48c21 |
hex | 1f5c62cdefb |
2155103444731 has 4 divisors (see below), whose sum is σ = 2170607786200. Its totient is φ = 2139599103264.
The previous prime is 2155103444701. The next prime is 2155103444737. The reversal of 2155103444731 is 1374443015512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2155103444731 - 25 = 2155103444699 is a prime.
It is a super-2 number, since 2×21551034447312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2155103444737) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7752170526 + ... + 7752170803.
It is an arithmetic number, because the mean of its divisors is an integer number (542651946550).
Almost surely, 22155103444731 is an apocalyptic number.
2155103444731 is a deficient number, since it is larger than the sum of its proper divisors (15504341469).
2155103444731 is a wasteful number, since it uses less digits than its factorization.
2155103444731 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15504341468.
The product of its (nonzero) digits is 201600, while the sum is 40.
The spelling of 2155103444731 in words is "two trillion, one hundred fifty-five billion, one hundred three million, four hundred forty-four thousand, seven hundred thirty-one".
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