Base | Representation |
---|---|
bin | 11111010111001000011… |
… | …100010001110001110011 |
3 | 21122000210111220011121100 |
4 | 133113020130101301303 |
5 | 240302212204040342 |
6 | 4330020333055443 |
7 | 311463262152504 |
oct | 37271034216163 |
9 | 7560714804540 |
10 | 2155141471347 |
11 | 760a991a3507 |
12 | 2a9820627583 |
13 | 1282c9076367 |
14 | 7644900abab |
15 | 3b0d815ae4c |
hex | 1f5c8711c73 |
2155141471347 has 12 divisors (see below), whose sum is σ = 3140530641144. Its totient is φ = 1424046281280.
The previous prime is 2155141471333. The next prime is 2155141471363. The reversal of 2155141471347 is 7431741415512.
2155141471347 is a `hidden beast` number, since 2 + 1 + 5 + 5 + 141 + 471 + 34 + 7 = 666.
It is not a de Polignac number, because 2155141471347 - 26 = 2155141471283 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2155141471397) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1059557229 + ... + 1059559262.
It is an arithmetic number, because the mean of its divisors is an integer number (261710886762).
Almost surely, 22155141471347 is an apocalyptic number.
2155141471347 is a deficient number, since it is larger than the sum of its proper divisors (985389169797).
2155141471347 is a wasteful number, since it uses less digits than its factorization.
2155141471347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2119116610 (or 2119116607 counting only the distinct ones).
The product of its digits is 470400, while the sum is 45.
Adding to 2155141471347 its reverse (7431741415512), we get a palindrome (9586882886859).
It can be divided in two parts, 215514 and 1471347, that added together give a palindrome (1686861).
The spelling of 2155141471347 in words is "two trillion, one hundred fifty-five billion, one hundred forty-one million, four hundred seventy-one thousand, three hundred forty-seven".
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