Base | Representation |
---|---|
bin | 11111010111010011111… |
… | …000101000000111011011 |
3 | 21122001021220010210220012 |
4 | 133113103320220013123 |
5 | 240303110330433001 |
6 | 4330051351552135 |
7 | 311501113030550 |
oct | 37272370500733 |
9 | 7561256123805 |
10 | 2155333452251 |
11 | 7610875a9611 |
12 | 2a987498b64b |
13 | 128329a83625 |
14 | 76466702a27 |
15 | 3b0e9e2e2bb |
hex | 1f5d3e281db |
2155333452251 has 16 divisors (see below), whose sum is σ = 2467257508608. Its totient is φ = 1844415208800.
The previous prime is 2155333452197. The next prime is 2155333452319. The reversal of 2155333452251 is 1522543335512.
It is a cyclic number.
It is not a de Polignac number, because 2155333452251 - 214 = 2155333435867 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2155333452199 and 2155333452208.
It is not an unprimeable number, because it can be changed into a prime (2155333472251) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28224461 + ... + 28300721.
It is an arithmetic number, because the mean of its divisors is an integer number (154203594288).
Almost surely, 22155333452251 is an apocalyptic number.
2155333452251 is a deficient number, since it is larger than the sum of its proper divisors (311924056357).
2155333452251 is an equidigital number, since it uses as much as digits as its factorization.
2155333452251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82802.
The product of its digits is 540000, while the sum is 41.
Adding to 2155333452251 its reverse (1522543335512), we get a palindrome (3677876787763).
The spelling of 2155333452251 in words is "two trillion, one hundred fifty-five billion, three hundred thirty-three million, four hundred fifty-two thousand, two hundred fifty-one".
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