Base | Representation |
---|---|
bin | 11111011001000011001… |
… | …111010101011101110011 |
3 | 21122020010002112102021211 |
4 | 133121003033111131303 |
5 | 240320422112114042 |
6 | 4331001010300551 |
7 | 311565316463500 |
oct | 37310317253563 |
9 | 7566102472254 |
10 | 2157201676147 |
11 | 761956120901 |
12 | 2aa0b6587757 |
13 | 128566b3c95b |
14 | 765a28984a7 |
15 | 3b1a8e62017 |
hex | 1f6433d5773 |
2157201676147 has 12 divisors (see below), whose sum is σ = 2513104550640. Its totient is φ = 1846298768496.
The previous prime is 2157201676127. The next prime is 2157201676151. The reversal of 2157201676147 is 7416761027512.
It is not a de Polignac number, because 2157201676147 - 215 = 2157201643379 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (49).
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2157201676147.
It is not an unprimeable number, because it can be changed into a prime (2157201676127) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 32481247 + ... + 32547592.
It is an arithmetic number, because the mean of its divisors is an integer number (209425379220).
Almost surely, 22157201676147 is an apocalyptic number.
2157201676147 is a deficient number, since it is larger than the sum of its proper divisors (355902874493).
2157201676147 is an equidigital number, since it uses as much as digits as its factorization.
2157201676147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65029530 (or 65029523 counting only the distinct ones).
The product of its (nonzero) digits is 987840, while the sum is 49.
The spelling of 2157201676147 in words is "two trillion, one hundred fifty-seven billion, two hundred one million, six hundred seventy-six thousand, one hundred forty-seven".
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