Base | Representation |
---|---|
bin | 11111011111011100001… |
… | …110000001101100001001 |
3 | 21122212211021201200012012 |
4 | 133133130032001230021 |
5 | 240424000140324340 |
6 | 4334053521025305 |
7 | 312230334550154 |
oct | 37373416015411 |
9 | 7585737650165 |
10 | 2164063214345 |
11 | 7648572a402a |
12 | 2ab4b0485235 |
13 | 1290bb556726 |
14 | 76a53c90c9b |
15 | 3b45b52a565 |
hex | 1f7dc381b09 |
2164063214345 has 4 divisors (see below), whose sum is σ = 2596875857220. Its totient is φ = 1731250571472.
The previous prime is 2164063214323. The next prime is 2164063214353. The reversal of 2164063214345 is 5434123604612.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1117654924864 + 1046408289481 = 1057192^2 + 1022941^2 .
It is a cyclic number.
It is not a de Polignac number, because 2164063214345 - 224 = 2164046437129 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216406321430 + ... + 216406321439.
It is an arithmetic number, because the mean of its divisors is an integer number (649218964305).
Almost surely, 22164063214345 is an apocalyptic number.
It is an amenable number.
2164063214345 is a deficient number, since it is larger than the sum of its proper divisors (432812642875).
2164063214345 is an equidigital number, since it uses as much as digits as its factorization.
2164063214345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 432812642874.
The product of its (nonzero) digits is 414720, while the sum is 41.
Adding to 2164063214345 its reverse (5434123604612), we get a palindrome (7598186818957).
The spelling of 2164063214345 in words is "two trillion, one hundred sixty-four billion, sixty-three million, two hundred fourteen thousand, three hundred forty-five".
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