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2166165014313 = 3722055004771
BaseRepresentation
bin11111100001011001011…
…111110000011100101001
321200002020202122011201110
4133201121133300130221
5240442301220424223
64335042241540533
7312333405551646
oct37413137603451
97602222564643
102166165014313
117657357514a3
122ab998344749
13129364b24951
1476bb3088dcd
153b530cead93
hex1f8597f0729

2166165014313 has 4 divisors (see below), whose sum is σ = 2888220019088. Its totient is φ = 1444110009540.

The previous prime is 2166165014263. The next prime is 2166165014323. The reversal of 2166165014313 is 3134105616612.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2166165014313 - 213 = 2166165006121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (2166165014323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 361027502383 + ... + 361027502388.

It is an arithmetic number, because the mean of its divisors is an integer number (722055004772).

Almost surely, 22166165014313 is an apocalyptic number.

It is an amenable number.

2166165014313 is a deficient number, since it is larger than the sum of its proper divisors (722055004775).

2166165014313 is an equidigital number, since it uses as much as digits as its factorization.

2166165014313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 722055004774.

The product of its (nonzero) digits is 77760, while the sum is 39.

The spelling of 2166165014313 in words is "two trillion, one hundred sixty-six billion, one hundred sixty-five million, fourteen thousand, three hundred thirteen".

Divisors: 1 3 722055004771 2166165014313