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21712015153 = 39435506471
BaseRepresentation
bin10100001110001000…
…110000111100110001
32002001010222122112101
4110032020300330301
5323431233441103
613550243500401
71366021040503
oct241610607461
962033878471
1021712015153
119231959384
12425b387701
1320802a005a
14109d817d73
158711e4a1d
hex50e230f31

21712015153 has 4 divisors (see below), whose sum is σ = 21717525568. Its totient is φ = 21706504740.

The previous prime is 21712015121. The next prime is 21712015207. The reversal of 21712015153 is 35151021712.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21712015153 - 25 = 21712015121 is a prime.

It is a super-2 number, since 2×217120151532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21712015553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2749293 + ... + 2757178.

It is an arithmetic number, because the mean of its divisors is an integer number (5429381392).

Almost surely, 221712015153 is an apocalyptic number.

It is an amenable number.

21712015153 is a deficient number, since it is larger than the sum of its proper divisors (5510415).

21712015153 is an equidigital number, since it uses as much as digits as its factorization.

21712015153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5510414.

The product of its (nonzero) digits is 2100, while the sum is 28.

Adding to 21712015153 its reverse (35151021712), we get a palindrome (56863036865).

The spelling of 21712015153 in words is "twenty-one billion, seven hundred twelve million, fifteen thousand, one hundred fifty-three".

Divisors: 1 3943 5506471 21712015153