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22001121000121 = 43511653976747
BaseRepresentation
bin1010000000010100010010…
…00000000111101010111001
32212220021201221200001200211
411000022021000013222321
510340431243434000441
6114443101522031121
74430346200615614
oct500121100075271
985807657601624
1022001121000121
1170126942668aa
122573b6aaa84a1
13c37909b6c493
14560c0795517b
15282476496a81
hex140289007ab9

22001121000121 has 4 divisors (see below), whose sum is σ = 22512774976912. Its totient is φ = 21489467023332.

The previous prime is 22001121000109. The next prime is 22001121000163. The reversal of 22001121000121 is 12100012110022.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22001121000121 - 213 = 22001120991929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (22001121007121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255826988331 + ... + 255826988416.

It is an arithmetic number, because the mean of its divisors is an integer number (5628193744228).

Almost surely, 222001121000121 is an apocalyptic number.

It is an amenable number.

22001121000121 is a deficient number, since it is larger than the sum of its proper divisors (511653976791).

22001121000121 is an equidigital number, since it uses as much as digits as its factorization.

22001121000121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 511653976790.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 22001121000121 its reverse (12100012110022), we get a palindrome (34101133110143).

The spelling of 22001121000121 in words is "twenty-two trillion, one billion, one hundred twenty-one million, one hundred twenty-one", and thus it is an aban number.

Divisors: 1 43 511653976747 22001121000121