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2200131134113 = 11381323524521
BaseRepresentation
bin100000000001000010000…
…010001110001010100001
321210022220220212211122111
4200001002002032022201
5242021332032242423
64402420513435321
7314645205035203
oct40010202161241
97708826784574
102200131134113
11779085738a90
122b649756bb41
1312c618aa82a3
14786b6148773
153c36cc0660d
hex2004208e2a1

2200131134113 has 8 divisors (see below), whose sum is σ = 2400153925536. Its totient is φ = 2000110154400.

The previous prime is 2200131134087. The next prime is 2200131134129. The reversal of 2200131134113 is 3114311310022.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2200131134113 - 29 = 2200131133601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2200131134413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3932293 + ... + 4456813.

It is an arithmetic number, because the mean of its divisors is an integer number (300019240692).

Almost surely, 22200131134113 is an apocalyptic number.

It is an amenable number.

2200131134113 is a deficient number, since it is larger than the sum of its proper divisors (200022791423).

2200131134113 is a wasteful number, since it uses less digits than its factorization.

2200131134113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 905855.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 2200131134113 its reverse (3114311310022), we get a palindrome (5314442444135).

The spelling of 2200131134113 in words is "two trillion, two hundred billion, one hundred thirty-one million, one hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 11 381323 524521 4194553 5769731 200011921283 2200131134113