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22002312115 = 57628637489
BaseRepresentation
bin10100011111011100…
…001010001110110011
32002210101020021002201
4110133130022032303
5330030042441430
614035133524031
71406144365360
oct243734121663
962711207081
1022002312115
119370805823
124320643617
1320c84814c4
1410ca1c3467
1588b9388ca
hex51f70a3b3

22002312115 has 8 divisors (see below), whose sum is σ = 30174599520. Its totient is φ = 15087299712.

The previous prime is 22002312097. The next prime is 22002312121. The reversal of 22002312115 is 51121320022.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 22002312115 - 29 = 22002311603 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22002312092 and 22002312101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 314318710 + ... + 314318779.

It is an arithmetic number, because the mean of its divisors is an integer number (3771824940).

Almost surely, 222002312115 is an apocalyptic number.

22002312115 is a deficient number, since it is larger than the sum of its proper divisors (8172287405).

22002312115 is an equidigital number, since it uses as much as digits as its factorization.

22002312115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 628637501.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 22002312115 its reverse (51121320022), we get a palindrome (73123632137).

The spelling of 22002312115 in words is "twenty-two billion, two million, three hundred twelve thousand, one hundred fifteen".

Divisors: 1 5 7 35 628637489 3143187445 4400462423 22002312115