2200311302131 has 4 divisors (see below), whose sum is σ = 2200490741232. Its totient is φ = 2200131863032.

The previous prime is 2200311302113. The next prime is 2200311302173. The reversal of 2200311302131 is 1312031130022.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2200311302131 - 2¹⁵ = 2200311269363 is a prime.

It is a super-2 number, since 2×2200311302131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2200311302099 and 2200311302108.

It is not an unprimeable number, because it can be changed into a prime (2200311302191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89701156 + ... + 89725681.

It is an arithmetic number, because the mean of its divisors is an integer number (550122685308).

Almost surely, 2^{2200311302131} is an apocalyptic number.

2200311302131 is a deficient number, since it is larger than the sum of its proper divisors (179439101).

2200311302131 is a wasteful number, since it uses less digits than its factorization.

2200311302131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 179439100.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2200311302131 its reverse (1312031130022), we get a palindrome (3512342432153).

The spelling of 2200311302131 in words is "two trillion, two hundred billion, three hundred eleven million, three hundred two thousand, one hundred thirty-one".