Base | Representation |
---|---|
bin | 10100100000100111… |
… | …010011100011101001 |
3 | 2002211202022002001020 |
4 | 110200213103203221 |
5 | 330100113323423 |
6 | 14041120043053 |
7 | 1406504002014 |
oct | 244047234351 |
9 | 62752262036 |
10 | 22022011113 |
11 | 938093a993 |
12 | 4327163489 |
13 | 20cc58a90b |
14 | 10cca7037b |
15 | 88d52a4e3 |
hex | 5209d38e9 |
22022011113 has 4 divisors (see below), whose sum is σ = 29362681488. Its totient is φ = 14681340740.
The previous prime is 22022011087. The next prime is 22022011133. The reversal of 22022011113 is 31111022022.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 22022011113 - 26 = 22022011049 is a prime.
It is a super-2 number, since 2×220220111132 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 22022011092 and 22022011101.
It is not an unprimeable number, because it can be changed into a prime (22022011133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3670335183 + ... + 3670335188.
It is an arithmetic number, because the mean of its divisors is an integer number (7340670372).
Almost surely, 222022011113 is an apocalyptic number.
It is an amenable number.
22022011113 is a deficient number, since it is larger than the sum of its proper divisors (7340670375).
22022011113 is an equidigital number, since it uses as much as digits as its factorization.
22022011113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7340670374.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 22022011113 its reverse (31111022022), we get a palindrome (53133033135).
The spelling of 22022011113 in words is "twenty-two billion, twenty-two million, eleven thousand, one hundred thirteen".
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