Base | Representation |
---|---|
bin | 1010000011001100100010… |
… | …01110110100111100011001 |
3 | 2220020202002000110122021012 |
4 | 11001212101032310330121 |
5 | 10344041342042233423 |
6 | 115000341510423305 |
7 | 4440450450515042 |
oct | 501462116647431 |
9 | 86222060418235 |
10 | 22100043321113 |
11 | 705063734279a |
12 | 258b177961b35 |
13 | c44043314c24 |
14 | 56590d8078c9 |
15 | 284d15ca9078 |
hex | 1419913b4f19 |
22100043321113 has 4 divisors (see below), whose sum is σ = 22100294571648. Its totient is φ = 22099792070580.
The previous prime is 22100043321107. The next prime is 22100043321127. The reversal of 22100043321113 is 31112334000122.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 22100043321113 - 220 = 22100042272537 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (22100043321193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125493281 + ... + 125669262.
It is an arithmetic number, because the mean of its divisors is an integer number (5525073642912).
Almost surely, 222100043321113 is an apocalyptic number.
It is an amenable number.
22100043321113 is a deficient number, since it is larger than the sum of its proper divisors (251250535).
22100043321113 is an equidigital number, since it uses as much as digits as its factorization.
22100043321113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 251250534.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 22100043321113 its reverse (31112334000122), we get a palindrome (53212377321235).
The spelling of 22100043321113 in words is "twenty-two trillion, one hundred billion, forty-three million, three hundred twenty-one thousand, one hundred thirteen".
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