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22102441124433 = 321147597337039
BaseRepresentation
bin1010000011010001000000…
…01001101110001001010001
32220020222021010100200001120
411001220200021232021101
510344111244411440213
6115001415443552453
74440564044512215
oct501504011561121
986228233320046
1022102441124433
11705165789492a
12258b72698b729
13c44336011a67
14565a9a054945
15284e06549423
hex141a2026e251

22102441124433 has 16 divisors (see below), whose sum is σ = 29615815219200. Its totient is φ = 14662043257680.

The previous prime is 22102441124377. The next prime is 22102441124441. The reversal of 22102441124433 is 33442114420122.

It is not a de Polignac number, because 22102441124433 - 29 = 22102441123921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22102441124394 and 22102441124403.

It is not an unprimeable number, because it can be changed into a prime (22102441124483) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 656073 + ... + 6680966.

It is an arithmetic number, because the mean of its divisors is an integer number (1850988451200).

Almost surely, 222102441124433 is an apocalyptic number.

It is an amenable number.

22102441124433 is a deficient number, since it is larger than the sum of its proper divisors (7513374094767).

22102441124433 is a wasteful number, since it uses less digits than its factorization.

22102441124433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7342012.

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 22102441124433 its reverse (33442114420122), we get a palindrome (55544555544555).

The spelling of 22102441124433 in words is "twenty-two trillion, one hundred two billion, four hundred forty-one million, one hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 3 211 633 4759 14277 1004149 3012447 7337039 22011117 1548115229 4644345687 34916968601 104750905803 7367480374811 22102441124433