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2211102320131 = 3135717051361
BaseRepresentation
bin100000001011001111111…
…101111110011000000011
321211101020112002211112101
4200023033331332120003
5242211314143221011
64411433312211231
7315514114422235
oct40131775763003
97741215084471
102211102320131
117827a5686471
122b8639839b17
13130676a54733
1479037278255
153c7b0ea32c1
hex202cff7e603

2211102320131 has 4 divisors (see below), whose sum is σ = 2211109685064. Its totient is φ = 2211094955200.

The previous prime is 2211102320033. The next prime is 2211102320249. The reversal of 2211102320131 is 1310232011122.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2211102320131 - 27 = 2211102320003 is a prime.

It is a super-2 number, since 2×22111023201312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2211102320099 and 2211102320108.

It is not an unprimeable number, because it can be changed into a prime (2211102320831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3212110 + ... + 3839251.

It is an arithmetic number, because the mean of its divisors is an integer number (552777421266).

Almost surely, 22211102320131 is an apocalyptic number.

2211102320131 is a deficient number, since it is larger than the sum of its proper divisors (7364933).

2211102320131 is an equidigital number, since it uses as much as digits as its factorization.

2211102320131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7364932.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2211102320131 its reverse (1310232011122), we get a palindrome (3521334331253).

The spelling of 2211102320131 in words is "two trillion, two hundred eleven billion, one hundred two million, three hundred twenty thousand, one hundred thirty-one".

Divisors: 1 313571 7051361 2211102320131