Base | Representation |
---|---|
bin | 10100100110001010… |
… | …011010101011111001 |
3 | 2010002020110112221212 |
4 | 110212022122223321 |
5 | 330242431221213 |
6 | 14054243212505 |
7 | 1412014155245 |
oct | 244612325371 |
9 | 63066415855 |
10 | 22115101433 |
11 | 9419442037 |
12 | 4352377135 |
13 | 2115952349 |
14 | 10db183425 |
15 | 8967b79a8 |
hex | 52629aaf9 |
22115101433 has 8 divisors (see below), whose sum is σ = 23289909600. Its totient is φ = 20941378848.
The previous prime is 22115101417. The next prime is 22115101441. The reversal of 22115101433 is 33410151122.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 22115101433 - 24 = 22115101417 is a prime.
It is a super-2 number, since 2×221151014332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 22115101399 and 22115101408.
It is not an unprimeable number, because it can be changed into a prime (22115101403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 229403 + ... + 311216.
It is an arithmetic number, because the mean of its divisors is an integer number (2911238700).
Almost surely, 222115101433 is an apocalyptic number.
It is an amenable number.
22115101433 is a deficient number, since it is larger than the sum of its proper divisors (1174808167).
22115101433 is a wasteful number, since it uses less digits than its factorization.
22115101433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 542791.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 22115101433 its reverse (33410151122), we get a palindrome (55525252555).
The spelling of 22115101433 in words is "twenty-two billion, one hundred fifteen million, one hundred one thousand, four hundred thirty-three".
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