Search a number
-
+
221202001113 = 33110921821249
BaseRepresentation
bin1100111000000010101…
…0101010110011011001
3210010221221120221021220
43032000222222303121
512111010203013423
6245341354322253
721660406662222
oct3160052526331
9703857527256
10221202001113
11858a1843475
1236a54129389
1317b22a3c072
14a9c5c98249
155b499c39e3
hex3380aaacd9

221202001113 has 16 divisors (see below), whose sum is σ = 307243200000. Its totient is φ = 141401687040.

The previous prime is 221202001103. The next prime is 221202001183. The reversal of 221202001113 is 311100202122.

It is a de Polignac number, because none of the positive numbers 2k-221202001113 is a prime.

It is a super-4 number, since 4×2212020011134 (a number of 46 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 221202001092 and 221202001101.

It is not an unprimeable number, because it can be changed into a prime (221202001103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10900488 + ... + 10920761.

It is an arithmetic number, because the mean of its divisors is an integer number (19202700000).

Almost surely, 2221202001113 is an apocalyptic number.

It is an amenable number.

221202001113 is a deficient number, since it is larger than the sum of its proper divisors (86041198887).

221202001113 is a wasteful number, since it uses less digits than its factorization.

221202001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21821392.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 221202001113 its reverse (311100202122), we get a palindrome (532302203235).

The spelling of 221202001113 in words is "two hundred twenty-one billion, two hundred two million, one thousand, one hundred thirteen".

Divisors: 1 3 31 93 109 327 3379 10137 21821249 65463747 676458719 2029376157 2378516141 7135548423 73734000371 221202001113