Base | Representation |
---|---|
bin | 100000001100001100101… |
… | …011111011100010110001 |
3 | 21211110212111221010202121 |
4 | 200030030223323202301 |
5 | 242220410434000423 |
6 | 4412122342114241 |
7 | 315551264153563 |
oct | 40141453734261 |
9 | 7743774833677 |
10 | 2212121000113 |
11 | 7831786a8852 |
12 | 2b8882a1b981 |
13 | 1307a9b0225b |
14 | 790d2689333 |
15 | 3c82062445d |
hex | 2030cafb8b1 |
2212121000113 has 8 divisors (see below), whose sum is σ = 2244576096000. Its totient is φ = 2179777243488.
The previous prime is 2212121000101. The next prime is 2212121000129. The reversal of 2212121000113 is 3110001212122.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2212121000113 - 213 = 2212120991921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2212121000153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27794788 + ... + 27874261.
It is an arithmetic number, because the mean of its divisors is an integer number (280572012000).
Almost surely, 22212121000113 is an apocalyptic number.
It is an amenable number.
2212121000113 is a deficient number, since it is larger than the sum of its proper divisors (32455095887).
2212121000113 is an equidigital number, since it uses as much as digits as its factorization.
2212121000113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55669631.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2212121000113 its reverse (3110001212122), we get a palindrome (5322122212235).
The spelling of 2212121000113 in words is "two trillion, two hundred twelve billion, one hundred twenty-one million, one hundred thirteen", and thus it is an aban number.
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