Base | Representation |
---|---|
bin | 100000001100011000100… |
… | …111010111100111111011 |
3 | 21211111101110111211201210 |
4 | 200030120213113213323 |
5 | 242221313202143003 |
6 | 4412154251414203 |
7 | 315556244224554 |
oct | 40143047274773 |
9 | 7744343454653 |
10 | 2212321131003 |
11 | 783270670085 |
12 | 2b8919a54363 |
13 | 13080c403cb9 |
14 | 791110a332b |
15 | 3c832ea7503 |
hex | 203189d79fb |
2212321131003 has 8 divisors (see below), whose sum is σ = 3078012008448. Its totient is φ = 1410755503784.
The previous prime is 2212321131001. The next prime is 2212321131017. The reversal of 2212321131003 is 3001311232122.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2212321131003 - 21 = 2212321131001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2212321131001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16031312475 + ... + 16031312612.
It is an arithmetic number, because the mean of its divisors is an integer number (384751501056).
Almost surely, 22212321131003 is an apocalyptic number.
2212321131003 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2212321131003 is a deficient number, since it is larger than the sum of its proper divisors (865690877445).
2212321131003 is a wasteful number, since it uses less digits than its factorization.
2212321131003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32062625113.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 2212321131003 its reverse (3001311232122), we get a palindrome (5213632363125).
The spelling of 2212321131003 in words is "two trillion, two hundred twelve billion, three hundred twenty-one million, one hundred thirty-one thousand, three".
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