Base | Representation |
---|---|
bin | 100000001101000001010… |
… | …101011111110111101001 |
3 | 21211120011002001000221012 |
4 | 200031001111133313221 |
5 | 242224213100441131 |
6 | 4412350134353305 |
7 | 315612211166165 |
oct | 40150125376751 |
9 | 7746132030835 |
10 | 2213004312041 |
11 | 783591272106 |
12 | 2b8a8a7bb835 |
13 | 1308bab04b33 |
14 | 79177addca5 |
15 | 3c872e5652b |
hex | 2034155fde9 |
2213004312041 has 4 divisors (see below), whose sum is σ = 2213361312000. Its totient is φ = 2212647312084.
The previous prime is 2213004312019. The next prime is 2213004312047. The reversal of 2213004312041 is 1402134003122.
2213004312041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2213004312041 - 226 = 2212937203177 is a prime.
It is a super-2 number, since 2×22130043120412 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2213004311998 and 2213004312016.
It is not an unprimeable number, because it can be changed into a prime (2213004312047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178490681 + ... + 178503078.
It is an arithmetic number, because the mean of its divisors is an integer number (553340328000).
Almost surely, 22213004312041 is an apocalyptic number.
It is an amenable number.
2213004312041 is a deficient number, since it is larger than the sum of its proper divisors (356999959).
2213004312041 is an equidigital number, since it uses as much as digits as its factorization.
2213004312041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 356999958.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 2213004312041 its reverse (1402134003122), we get a palindrome (3615138315163).
The spelling of 2213004312041 in words is "two trillion, two hundred thirteen billion, four million, three hundred twelve thousand, forty-one".
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