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22141113 = 37380371
BaseRepresentation
bin101010001110…
…1100010111001
31112122212220020
41110131202321
521132003423
62110321053
7356124231
oct124354271
945585806
1022141113
1111552a45
1274b9189
134782b67
142d24cc1
151e254e3
hex151d8b9

22141113 has 4 divisors (see below), whose sum is σ = 29521488. Its totient is φ = 14760740.

The previous prime is 22141081. The next prime is 22141117. The reversal of 22141113 is 31114122.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22141113 - 25 = 22141081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22141092 and 22141101.

It is not an unprimeable number, because it can be changed into a prime (22141117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3690183 + ... + 3690188.

It is an arithmetic number, because the mean of its divisors is an integer number (7380372).

Almost surely, 222141113 is an apocalyptic number.

It is an amenable number.

22141113 is a deficient number, since it is larger than the sum of its proper divisors (7380375).

22141113 is an equidigital number, since it uses as much as digits as its factorization.

22141113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7380374.

The product of its digits is 48, while the sum is 15.

The square root of 22141113 is about 4705.4344114014. The cubic root of 22141113 is about 280.8017539318.

Adding to 22141113 its reverse (31114122), we get a palindrome (53255235).

The spelling of 22141113 in words is "twenty-two million, one hundred forty-one thousand, one hundred thirteen".

Divisors: 1 3 7380371 22141113