Base | Representation |
---|---|
bin | 100000010110011100100… |
… | …001011100110011000001 |
3 | 21212112021100012212001220 |
4 | 200112130201130303001 |
5 | 242410424232401213 |
6 | 4421142240545253 |
7 | 316421042055006 |
oct | 40263441346301 |
9 | 7775240185056 |
10 | 2223124106433 |
11 | 78790466844a |
12 | 2baa33922229 |
13 | 131841576759 |
14 | 79857b278ad |
15 | 3cc665c8e23 |
hex | 2059c85ccc1 |
2223124106433 has 12 divisors (see below), whose sum is σ = 3046443266160. Its totient is φ = 1442026444752.
The previous prime is 2223124106431. The next prime is 2223124106449. The reversal of 2223124106433 is 3346014213222.
It is not a de Polignac number, because 2223124106433 - 21 = 2223124106431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2223124106394 and 2223124106403.
It is not an unprimeable number, because it can be changed into a prime (2223124106431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 270646503 + ... + 270654716.
It is an arithmetic number, because the mean of its divisors is an integer number (253870272180).
Almost surely, 22223124106433 is an apocalyptic number.
It is an amenable number.
2223124106433 is a deficient number, since it is larger than the sum of its proper divisors (823319159727).
2223124106433 is an equidigital number, since it uses as much as digits as its factorization.
2223124106433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 541301296 (or 541301259 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 2223124106433 its reverse (3346014213222), we get a palindrome (5569138319655).
The spelling of 2223124106433 in words is "two trillion, two hundred twenty-three billion, one hundred twenty-four million, one hundred six thousand, four hundred thirty-three".
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