22323143314113 has 4 divisors (see below), whose sum is σ = 29764191085488. Its totient is φ = 14882095542740.

The previous prime is 22323143314081. The next prime is 22323143314139. The reversal of 22323143314113 is 31141334132322.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22323143314113 - 2⁵ = 22323143314081 is a prime.

It is a super-3 number, since 3×22323143314113³ (a number of 41 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (22323143314193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3720523885683 + ... + 3720523885688.

It is an arithmetic number, because the mean of its divisors is an integer number (7441047771372).

Almost surely, 2^{22323143314113} is an apocalyptic number.

It is an amenable number.

22323143314113 is a deficient number, since it is larger than the sum of its proper divisors (7441047771375).

22323143314113 is an equidigital number, since it uses as much as digits as its factorization.

22323143314113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7441047771374.

The product of its digits is 31104, while the sum is 33.

Adding to 22323143314113 its reverse (31141334132322), we get a palindrome (53464477446435).

The spelling of 22323143314113 in words is "twenty-two trillion, three hundred twenty-three billion, one hundred forty-three million, three hundred fourteen thousand, one hundred thirteen".