Base | Representation |
---|---|
bin | 10100110111001101… |
… | …000101011010111001 |
3 | 2010211011110101111012 |
4 | 110313031011122321 |
5 | 331334124412213 |
6 | 14142455243305 |
7 | 1422055321031 |
oct | 246715053271 |
9 | 63734411435 |
10 | 22401013433 |
11 | 9555873a47 |
12 | 4412079535 |
13 | 215cc59946 |
14 | 112712a8c1 |
15 | 8b19424a8 |
hex | 5373456b9 |
22401013433 has 4 divisors (see below), whose sum is σ = 23580014160. Its totient is φ = 21222012708.
The previous prime is 22401013423. The next prime is 22401013499. The reversal of 22401013433 is 33431010422.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 22401013433 - 24 = 22401013417 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 22401013399 and 22401013408.
It is not an unprimeable number, because it can be changed into a prime (22401013423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 589500335 + ... + 589500372.
It is an arithmetic number, because the mean of its divisors is an integer number (5895003540).
Almost surely, 222401013433 is an apocalyptic number.
It is an amenable number.
22401013433 is a deficient number, since it is larger than the sum of its proper divisors (1179000727).
22401013433 is a wasteful number, since it uses less digits than its factorization.
22401013433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1179000726.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 22401013433 its reverse (33431010422), we get a palindrome (55832023855).
The spelling of 22401013433 in words is "twenty-two billion, four hundred one million, thirteen thousand, four hundred thirty-three".
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