Base | Representation |
---|---|
bin | 10100110111110100… |
… | …010111010000110011 |
3 | 2010211212211111220101 |
4 | 110313310113100303 |
5 | 331344243411011 |
6 | 14143504053231 |
7 | 1422241664410 |
oct | 246764272063 |
9 | 63755744811 |
10 | 22411310131 |
11 | 9560667011 |
12 | 4415604217 |
13 | 2162123572 |
14 | 112864b107 |
15 | 8b27c82c1 |
hex | 537d17433 |
22411310131 has 4 divisors (see below), whose sum is σ = 25612925872. Its totient is φ = 19209694392.
The previous prime is 22411310111. The next prime is 22411310167. The reversal of 22411310131 is 13101311422.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 22411310131 - 223 = 22402921523 is a prime.
It is a super-2 number, since 2×224113101312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 22411310099 and 22411310108.
It is not an unprimeable number, because it can be changed into a prime (22411310111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1600807860 + ... + 1600807873.
It is an arithmetic number, because the mean of its divisors is an integer number (6403231468).
Almost surely, 222411310131 is an apocalyptic number.
22411310131 is a deficient number, since it is larger than the sum of its proper divisors (3201615741).
22411310131 is an equidigital number, since it uses as much as digits as its factorization.
22411310131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3201615740.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 22411310131 its reverse (13101311422), we get a palindrome (35512621553).
The spelling of 22411310131 in words is "twenty-two billion, four hundred eleven million, three hundred ten thousand, one hundred thirty-one".
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