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225061133147 = 342527657061
BaseRepresentation
bin1101000110011010110…
…0000101101101011011
3210111220220020011012222
43101212230011231123
512141411122230042
6251220333054255
722155140032064
oct3214654055533
9714826204188
10225061133147
11874a2162494
123775062738b
13182b940b346
14ac7061d56b
155cc36c02d2
hex3466b05b5b

225061133147 has 4 divisors (see below), whose sum is σ = 225062132736. Its totient is φ = 225060133560.

The previous prime is 225061133119. The next prime is 225061133191. The reversal of 225061133147 is 741331160522.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 225061133147 - 210 = 225061132123 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (225061133107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13997 + ... + 671057.

It is an arithmetic number, because the mean of its divisors is an integer number (56265533184).

Almost surely, 2225061133147 is an apocalyptic number.

225061133147 is a deficient number, since it is larger than the sum of its proper divisors (999589).

225061133147 is an equidigital number, since it uses as much as digits as its factorization.

225061133147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 999588.

The product of its (nonzero) digits is 30240, while the sum is 35.

Adding to 225061133147 its reverse (741331160522), we get a palindrome (966392293669).

The spelling of 225061133147 in words is "two hundred twenty-five billion, sixty-one million, one hundred thirty-three thousand, one hundred forty-seven".

Divisors: 1 342527 657061 225061133147