Base | Representation |
---|---|
bin | 1010010000010111010101… |
… | …00010100101111111001011 |
3 | 2221211222222102110010001111 |
4 | 11020023222202211333023 |
5 | 10424000021342203120 |
6 | 115544252003231151 |
7 | 4515236205416401 |
oct | 510135242457713 |
9 | 87758872403044 |
10 | 22552513241035 |
11 | 7205515866578 |
12 | 26429b30784b7 |
13 | c7790131cb5b |
14 | 57d79435b471 |
15 | 291998cd075a |
hex | 1482ea8a5fcb |
22552513241035 has 16 divisors (see below), whose sum is σ = 27303455241216. Its totient is φ = 17881728729088.
The previous prime is 22552513241017. The next prime is 22552513241039. The reversal of 22552513241035 is 53014231525522.
It is a cyclic number.
It is not a de Polignac number, because 22552513241035 - 241 = 20353489985483 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (22552513241039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16030347 + ... + 17380363.
It is an arithmetic number, because the mean of its divisors is an integer number (1706465952576).
Almost surely, 222552513241035 is an apocalyptic number.
22552513241035 is a deficient number, since it is larger than the sum of its proper divisors (4750942000181).
22552513241035 is a wasteful number, since it uses less digits than its factorization.
22552513241035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1379702.
The product of its (nonzero) digits is 360000, while the sum is 40.
Adding to 22552513241035 its reverse (53014231525522), we get a palindrome (75566744766557).
The spelling of 22552513241035 in words is "twenty-two trillion, five hundred fifty-two billion, five hundred thirteen million, two hundred forty-one thousand, thirty-five".
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