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230052414147 = 376684138049
BaseRepresentation
bin1101011001000000110…
…0010100001011000011
3210222210202012111120020
43112100030110023003
512232121404223042
6253403513344523
722422625153533
oct3262014241303
9728722174506
10230052414147
1189623654806
1238704108143
131890350645a
14b1c54914c3
155eb69a33ec
hex35903142c3

230052414147 has 4 divisors (see below), whose sum is σ = 306736552200. Its totient is φ = 153368276096.

The previous prime is 230052414089. The next prime is 230052414173. The reversal of 230052414147 is 741414250032.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 230052414147 - 26 = 230052414083 is a prime.

It is a super-2 number, since 2×2300524141472 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (230052414047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38342069022 + ... + 38342069027.

It is an arithmetic number, because the mean of its divisors is an integer number (76684138050).

Almost surely, 2230052414147 is an apocalyptic number.

230052414147 is a deficient number, since it is larger than the sum of its proper divisors (76684138053).

230052414147 is an equidigital number, since it uses as much as digits as its factorization.

230052414147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76684138052.

The product of its (nonzero) digits is 26880, while the sum is 33.

Adding to 230052414147 its reverse (741414250032), we get a palindrome (971466664179).

The spelling of 230052414147 in words is "two hundred thirty billion, fifty-two million, four hundred fourteen thousand, one hundred forty-seven".

Divisors: 1 3 76684138049 230052414147