Base | Representation |
---|---|
bin | 1101011001001100010… |
… | …1110011101111110001 |
3 | 210222221010200221211221 |
4 | 3112103011303233301 |
5 | 12232221331240423 |
6 | 253412411505041 |
7 | 22424055366310 |
oct | 3262305635761 |
9 | 728833627757 |
10 | 230101040113 |
11 | 8964904715a |
12 | 38718458181 |
13 | 18910600309 |
14 | b1cbb0c277 |
15 | 5ebadaae5d |
hex | 3593173bf1 |
230101040113 has 16 divisors (see below), whose sum is σ = 264155364864. Its totient is φ = 196344072000.
The previous prime is 230101040101. The next prime is 230101040179. The reversal of 230101040113 is 311040101032.
It is a cyclic number.
It is not a de Polignac number, because 230101040113 - 29 = 230101039601 is a prime.
It is a super-3 number, since 3×2301010401133 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (230101040413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1597431 + ... + 1735507.
It is an arithmetic number, because the mean of its divisors is an integer number (16509710304).
Almost surely, 2230101040113 is an apocalyptic number.
It is an amenable number.
230101040113 is a deficient number, since it is larger than the sum of its proper divisors (34054324751).
230101040113 is a wasteful number, since it uses less digits than its factorization.
230101040113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139152.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 230101040113 its reverse (311040101032), we get a palindrome (541141141145).
The spelling of 230101040113 in words is "two hundred thirty billion, one hundred one million, forty thousand, one hundred thirteen".
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