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230101040113 = 7317751138077
BaseRepresentation
bin1101011001001100010…
…1110011101111110001
3210222221010200221211221
43112103011303233301
512232221331240423
6253412411505041
722424055366310
oct3262305635761
9728833627757
10230101040113
118964904715a
1238718458181
1318910600309
14b1cbb0c277
155ebadaae5d
hex3593173bf1

230101040113 has 16 divisors (see below), whose sum is σ = 264155364864. Its totient is φ = 196344072000.

The previous prime is 230101040101. The next prime is 230101040179. The reversal of 230101040113 is 311040101032.

It is a cyclic number.

It is not a de Polignac number, because 230101040113 - 29 = 230101039601 is a prime.

It is a super-3 number, since 3×2301010401133 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (230101040413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1597431 + ... + 1735507.

It is an arithmetic number, because the mean of its divisors is an integer number (16509710304).

Almost surely, 2230101040113 is an apocalyptic number.

It is an amenable number.

230101040113 is a deficient number, since it is larger than the sum of its proper divisors (34054324751).

230101040113 is a wasteful number, since it uses less digits than its factorization.

230101040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139152.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 230101040113 its reverse (311040101032), we get a palindrome (541141141145).

The spelling of 230101040113 in words is "two hundred thirty billion, one hundred one million, forty thousand, one hundred thirteen".

Divisors: 1 7 317 751 2219 5257 138077 238067 966539 1666469 43770409 103695827 306392863 725870789 32871577159 230101040113