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23011133113 = 94724298979
BaseRepresentation
bin10101011011100100…
…100000011010111001
32012101200111200100101
4111123210200122321
5334111322224423
614323212235401
71443144255433
oct253344403271
965350450311
1023011133113
119839203991
12456246bb61
1322294896c7
141184189653
158ea2ad7ad
hex55b9206b9

23011133113 has 4 divisors (see below), whose sum is σ = 23035433040. Its totient is φ = 22986833188.

The previous prime is 23011133107. The next prime is 23011133143. The reversal of 23011133113 is 31133111032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23011133113 - 225 = 22977578681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23011133143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12148543 + ... + 12150436.

It is an arithmetic number, because the mean of its divisors is an integer number (5758858260).

Almost surely, 223011133113 is an apocalyptic number.

It is an amenable number.

23011133113 is a deficient number, since it is larger than the sum of its proper divisors (24299927).

23011133113 is an equidigital number, since it uses as much as digits as its factorization.

23011133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24299926.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 23011133113 its reverse (31133111032), we get a palindrome (54144244145).

The spelling of 23011133113 in words is "twenty-three billion, eleven million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 947 24298979 23011133113