Base | Representation |
---|---|
bin | 10101011011100100… |
… | …110001100000110001 |
3 | 2012101200122020101021 |
4 | 111123210301200301 |
5 | 334111331444441 |
6 | 14323213535441 |
7 | 1443144666514 |
oct | 253344614061 |
9 | 65350566337 |
10 | 23011203121 |
11 | 9839251545 |
12 | 45624a4581 |
13 | 22294b252a |
14 | 11841a6d7b |
15 | 8ea2c43d1 |
hex | 55b931831 |
23011203121 has 4 divisors (see below), whose sum is σ = 23015283712. Its totient is φ = 23007122532.
The previous prime is 23011203119. The next prime is 23011203197. The reversal of 23011203121 is 12130211032.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 23011203121 - 21 = 23011203119 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23011203095 and 23011203104.
It is not an unprimeable number, because it can be changed into a prime (23011203101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2031825 + ... + 2043118.
It is an arithmetic number, because the mean of its divisors is an integer number (5753820928).
Almost surely, 223011203121 is an apocalyptic number.
It is an amenable number.
23011203121 is a deficient number, since it is larger than the sum of its proper divisors (4080591).
23011203121 is an equidigital number, since it uses as much as digits as its factorization.
23011203121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4080590.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 23011203121 its reverse (12130211032), we get a palindrome (35141414153).
The spelling of 23011203121 in words is "twenty-three billion, eleven million, two hundred three thousand, one hundred twenty-one".
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