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23012010433 = 71324112823
BaseRepresentation
bin10101011011100111…
…110110100111000001
32012101202011020210201
4111123213312213001
5334112033313213
614323243125201
71443154601266
oct253347664701
965352136721
1023012010433
119839753045
124562813801
132229705b29
14118433726d
158ea3d36dd
hex55b9f69c1

23012010433 has 4 divisors (see below), whose sum is σ = 23336123328. Its totient is φ = 22687897540.

The previous prime is 23012010403. The next prime is 23012010443. The reversal of 23012010433 is 33401021032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23012010433 - 25 = 23012010401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 23012010433.

It is not an unprimeable number, because it can be changed into a prime (23012010403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162056341 + ... + 162056482.

It is an arithmetic number, because the mean of its divisors is an integer number (5834030832).

Almost surely, 223012010433 is an apocalyptic number.

It is an amenable number.

23012010433 is a deficient number, since it is larger than the sum of its proper divisors (324112895).

23012010433 is an equidigital number, since it uses as much as digits as its factorization.

23012010433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 324112894.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 23012010433 its reverse (33401021032), we get a palindrome (56413031465).

The spelling of 23012010433 in words is "twenty-three billion, twelve million, ten thousand, four hundred thirty-three".

Divisors: 1 71 324112823 23012010433