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230120133121 = 1544391490039
BaseRepresentation
bin1101011001010000111…
…0101001001000000001
3210222222110121222112101
43112110032221020001
512232241223224441
6253414333030401
722424406600124
oct3262416511001
9728873558471
10230120133121
11896588a7aaa
1238722925401
1318914556958
14b1d047c3bb
155ebc8cd231
hex35943a9201

230120133121 has 4 divisors (see below), whose sum is σ = 230121777600. Its totient is φ = 230118488644.

The previous prime is 230120133079. The next prime is 230120133149. The reversal of 230120133121 is 121331021032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-230120133121 is a prime.

It is a super-2 number, since 2×2301201331212 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (230120133161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590581 + ... + 899458.

It is an arithmetic number, because the mean of its divisors is an integer number (57530444400).

Almost surely, 2230120133121 is an apocalyptic number.

It is an amenable number.

230120133121 is a deficient number, since it is larger than the sum of its proper divisors (1644479).

230120133121 is a wasteful number, since it uses less digits than its factorization.

230120133121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1644478.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 230120133121 its reverse (121331021032), we get a palindrome (351451154153).

The spelling of 230120133121 in words is "two hundred thirty billion, one hundred twenty million, one hundred thirty-three thousand, one hundred twenty-one".

Divisors: 1 154439 1490039 230120133121