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23012013403 = 31742323013
BaseRepresentation
bin10101011011100111…
…110111010101011011
32012101202011101212201
4111123213313111123
5334112033412103
614323243151031
71443154613041
oct253347672533
965352141781
1023012013403
1198397552a5
124562815477
1322297072a2
141184338391
158ea3d451d
hex55b9f755b

23012013403 has 4 divisors (see below), whose sum is σ = 23754336448. Its totient is φ = 22269690360.

The previous prime is 23012013397. The next prime is 23012013439. The reversal of 23012013403 is 30431021032.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23012013403 - 217 = 23011882331 is a prime.

It is a super-3 number, since 3×230120134033 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23012013443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 371161476 + ... + 371161537.

It is an arithmetic number, because the mean of its divisors is an integer number (5938584112).

Almost surely, 223012013403 is an apocalyptic number.

23012013403 is a deficient number, since it is larger than the sum of its proper divisors (742323045).

23012013403 is an equidigital number, since it uses as much as digits as its factorization.

23012013403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 742323044.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 23012013403 its reverse (30431021032), we get a palindrome (53443034435).

The spelling of 23012013403 in words is "twenty-three billion, twelve million, thirteen thousand, four hundred three".

Divisors: 1 31 742323013 23012013403