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230130021113 = 713241267903
BaseRepresentation
bin1101011001010011010…
…0010111001011111001
3211000000011020100022022
43112110310113023321
512232301241133423
6253415325004225
722424556622106
oct3262464271371
9730004210268
10230130021113
1189663440aa3
12387260b3675
1318916609535
14b1d18d3aad
155ebd6d2dc8
hex3594d172f9

230130021113 has 4 divisors (see below), whose sum is σ = 233371289088. Its totient is φ = 226888753140.

The previous prime is 230130021109. The next prime is 230130021119. The reversal of 230130021113 is 311120031032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 230130021113 - 22 = 230130021109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 230130021091 and 230130021100.

It is not an unprimeable number, because it can be changed into a prime (230130021119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1620633881 + ... + 1620634022.

It is an arithmetic number, because the mean of its divisors is an integer number (58342822272).

Almost surely, 2230130021113 is an apocalyptic number.

It is an amenable number.

230130021113 is a deficient number, since it is larger than the sum of its proper divisors (3241267975).

230130021113 is an equidigital number, since it uses as much as digits as its factorization.

230130021113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3241267974.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 230130021113 its reverse (311120031032), we get a palindrome (541250052145).

The spelling of 230130021113 in words is "two hundred thirty billion, one hundred thirty million, twenty-one thousand, one hundred thirteen".

Divisors: 1 71 3241267903 230130021113