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23014312433 = 73287758919
BaseRepresentation
bin10101011011110000…
…101000100111110001
32012101220111012112222
4111123300220213301
5334113130444213
614323404330425
71443213266540
oct253360504761
965356435488
1023014312433
11983aa85622
124563543a15
13222a030868
141184776157
158ea6da808
hex55bc289f1

23014312433 has 4 divisors (see below), whose sum is σ = 26302071360. Its totient is φ = 19726553508.

The previous prime is 23014312423. The next prime is 23014312439. The reversal of 23014312433 is 33421341032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23014312433 - 216 = 23014246897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23014312439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1643879453 + ... + 1643879466.

It is an arithmetic number, because the mean of its divisors is an integer number (6575517840).

Almost surely, 223014312433 is an apocalyptic number.

It is an amenable number.

23014312433 is a deficient number, since it is larger than the sum of its proper divisors (3287758927).

23014312433 is an equidigital number, since it uses as much as digits as its factorization.

23014312433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3287758926.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 23014312433 its reverse (33421341032), we get a palindrome (56435653465).

The spelling of 23014312433 in words is "twenty-three billion, fourteen million, three hundred twelve thousand, four hundred thirty-three".

Divisors: 1 7 3287758919 23014312433